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CLAST TEST # 3 :                   

 8.  Workers who are being trained to perform a certain job are given a test.
       The scores on this test vary from  1 (lowest) to 5 (highest).
       The distribution of scores is shown in the following table. Find the mean score. 

Score Proportion

1

0.10

2 0.28
3 0.24
4 0.22
5 0.16

 

   
        A)  0.52              B) 1.00                  C)  2.26                      D)   3.06 
 

 Solution: 
      Note that finding the mean for data in a relative frequency table differs slightly from finding 
      the mean of data in a frequency table, because we don't know the size of the population
      (this would be the sum of the frequencies in a frequency table). In a relative frequency table like this,
      the sum of the proportions should always be 1. 

      To find the mean we find the sum of all terms formed by multiplying a value by its proportion.
      Mean = 1(0.10) + 2(0.28) + 3(0.24) + 4(0.22) + 5(0.16)
      Mean =  0.10 + 0.56 + 0.72 + 0.88 + 0.80
      Mean = 3.06

               

 Answer: D)   3.06 

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