Solution:    
                 3(2 - x) ≥ 5(x - 2)                     {5(x - 2) = 5x - 10}
                 3(2 - x) ≥ 5x - 10                      {3(2 - x) = 6 - 3x} 
                   6 - 3x ≥ 5x - 10                       (Add 3x to both sides)
                   6 - 3x  + 3x ≥ 5x + 3x - 10   
                   6 - 3x  + 3x ≥ 5x + 3x - 10
                   6 ≥ 5x + 3x - 10
                   6 ≥ 8x  - 10                             (Add 10 to both sides)
                   6 + 10 ≥ 8x  - 10 + 10          
                   6 + 10 ≥ 8x  - 10 + 10
                   6 + 10 ≥  8x  
                   16  ≥  8x                                 (Multiply each sides by 1/8)                         
                   16 (1/8)  ≥  8x  (1/8)
                     16/8  ≥  8x/8  
                         2  ≥  x     or    x  ≤ 2